Originally Posted by

**tester85** Hmmm. It took quite some time to solve this problem but finally i managed to figure it out. Hopefully it is correct

let x be the number of adult ticket sold

let y be the number of children ticket sold

6x + 3.5y = $2750 ............ Eqn 1

x - y = 250 ...................... Eqn2

We cannot solve the Eqn 1 and Eqn 2 directly as Eqn 1 involve cost and Eqn 2 involve quantity but it will help us solve the equation listed below

6(x-250) + 3.5y = 2750 - 6(250) where 250 are the number of tickets

Since x-250 = y ( derive from Eqn 2 )

6y + 3.5y = 1250

9.5y = 1250

y = 132

Resubstitute y = 132 into Eqn 1 or Eqn2 to get x, which is 382

I hope it helps