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At a movie theater, a cashier sold 250 more adult admission tickets than children'admission tickets. The adult's tickets were $6.00 each and the children's tickets were $3.50 each. What is the least number of each type of ticket that the cashier had to sell for the total
receipts to be at least $2,750?
Hmmm. It took quite some time to solve this problem but finally i managed to figure it out. Hopefully it is correct
let x be the number of adult ticket sold
let y be the number of children ticket sold
6x + 3.5y = $2750 ............ Eqn 1
x - y = 250 ...................... Eqn2
We cannot solve the Eqn 1 and Eqn 2 directly as Eqn 1 involve cost and Eqn 2 involve quantity but it will help us solve the equation listed below
6(x-250) + 3.5y = 2750 - 6(250) where 250 are the number of tickets
Since x-250 = y ( derive from Eqn 2 )
6y + 3.5y = 1250
9.5y = 1250
y = 132
Resubstitute y = 132 into Eqn 1 or Eqn2 to get x, which is 382
I hope it helps
Tell me, why is equation 2 x - y = 250 and NOTQuote:
Originally Posted by tester85
x + y = 250?
It is due to this statement " a cashier sold 250 more adult admission tickets than children'admission tickets "
Since we let x be the number of adult ticket sold
we let y be the number of children ticket sold
x - y = 250