Define x* by the equation x* = π – x. Then ((–π)*)* = (A) –2π (B) –1 (C) –π (D) 2π (E) 4π Answer: ((–π)*)* = (π – (–π))* = (π + π)* = (2π)* = π – 2π = –π. Choice C could someone make sense of this for me?
Follow Math Help Forum on Facebook and Google+
It has been given that x* = π – x lets say -n = x then (-n)* = n - (-n) = 2n then ((-n)*)* = (2n)* = n - 2n = -n
View Tag Cloud