You multiplied both sides of the equation by (-5y+7). The RHS is thus:
[(3y-2)/(-5y+7) + 5] * (-5y+7) = (3y-2) + 5*(-5y+7) = -22y + 33
You should be able to take it from here.
A suggestion: Please be more careful in your use of parenthesis. The function:
f(x) = 3x-2/-5x+7 = 3x + 2/(5x) + 7 = 3x + 7 + 2/(5x)
is not defined for x = 0 and apparently not what you intended. You meant to write:
f(x) = (3x-2)/(-5x+7)
It sounds picky, but it could cost you points on a test.