of this equation: x^2/25+y^2/36=1
I know the x-intercepts are (5, -5) and the y-intercepts are (6, -6), but don't know how to find the foci.
Please help!
You can answer me right here because I check often enough.
Joanne
of this equation: x^2/25+y^2/36=1
I know the x-intercepts are (5, -5) and the y-intercepts are (6, -6), but don't know how to find the foci.
Please help!
You can answer me right here because I check often enough.
Joanne
The definition of an ellipse a line. The sum of the distance to each foci of each point is the same.
You know because of the y-intercept that this is equal to
$\displaystyle (6+y)+(6-y) = 12 $
Then from the x-intercept you know that $\displaystyle 12 = 2\sqrt{5^2+y^2} $
$\displaystyle y =\pm \sqrt(11) $