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Math Help - Coins

  1. #1
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    Coins

    A coin bank contains nickels, dimes, and quarters totaling $5.45. If there ae twice as many quarters as dimes and 11 more nickels than quarters, how many of each coin are in the bank?

    My set up:

    x = number of dimes

    2x = number of quarters

    2x + 11 = number of nickels

    Is this correct so far?




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  2. #2
    Bar0n janvdl's Avatar
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    Quote Originally Posted by magentarita View Post
    A coin bank contains nickels, dimes, and quarters totaling $5.45. If there ae twice as many quarters as dimes and 11 more nickels than quarters, how many of each coin are in the bank?

    My set up:

    x = number of dimes

    2x = number of quarters

    2x + 11 = number of nickels

    Is this correct so far?

    Yes, it's correct. Now you only need to multiply the quantities with the values for Dimes, quarters, and nickels.

    (0,10)(x) + (0,25)(2x) + (0,05)(2x + 11) = 5,45

    Now solve for x.

    I find x = 7, and then you simply have to plug the values in.
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