Thread: Coins

A coin bank contains nickels, dimes, and quarters totaling $5.45. If there ae twice as many quarters as dimes and 11 more nickels than quarters, how many of each coin are in the bank?

My set up:

x = number of dimes

2x = number of quarters

2x + 11 = number of nickels

Is this correct so far?

Originally Posted by magentarita

A coin bank contains nickels, dimes, and quarters totaling $5.45. If there ae twice as many quarters as dimes and 11 more nickels than quarters, how many of each coin are in the bank?

My set up:

x = number of dimes

2x = number of quarters

2x + 11 = number of nickels

Is this correct so far?

Yes, it's correct. Now you only need to multiply the quantities with the values for Dimes, quarters, and nickels.

(0,10)(x) + (0,25)(2x) + (0,05)(2x + 11) = 5,45

Now solve for x.

I find x = 7, and then you simply have to plug the values in.