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Math Help - Quick question about fractions

  1. #1
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    Post Quick question about fractions

    If I have the fraction (x+2)/(x^2-9), where do I find the zeros -- the numerator or the denominator?

    Would the zeros of the equation be just -2, or would they be 3 and -3 (x+3, x-3 from the denominator)?

    Thanks for your help!
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  2. #2
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    Quote Originally Posted by live_laugh_luv27 View Post
    If I have the fraction (x+2)/(x^2-9), where do I find the zeros -- the numerator or the denominator?

    Would the zeros of the equation be just -2, or would they be 3 and -3 (x+3, x-3 from the denominator)?

    Thanks for your help!
    I assume you have a rational function here.

    f(x)=\frac{x+2}{(x+3)(x-3)}

    The zero in this case is -2. You have two vertical asymptotes at x=3 and x=-3
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  3. #3
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    Quote Originally Posted by masters View Post
    I assume you have a rational function here.

    f(x)=\frac{x+2}{(x+3)(x-3)}

    The zero in this case is -2. You have two vertical asymptotes at x=3 and x=-3
    That's what I thought...thanks for confirming
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