If I have the fraction (x+2)/(x^2-9), where do I find the zeros -- the numerator or the denominator? Would the zeros of the equation be just -2, or would they be 3 and -3 (x+3, x-3 from the denominator)? Thanks for your help!
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Originally Posted by live_laugh_luv27 If I have the fraction (x+2)/(x^2-9), where do I find the zeros -- the numerator or the denominator? Would the zeros of the equation be just -2, or would they be 3 and -3 (x+3, x-3 from the denominator)? Thanks for your help! I assume you have a rational function here. The zero in this case is -2. You have two vertical asymptotes at x=3 and x=-3
Originally Posted by masters I assume you have a rational function here. The zero in this case is -2. You have two vertical asymptotes at x=3 and x=-3 That's what I thought...thanks for confirming
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