1. ## Min/Max problem....need some help please

Find the maximum possible area of an isosceles triangle where the two equal sides are both 6cm long.

2. Originally Posted by Eric
Find the maximum possible area of an isosceles triangle where the two equal sides are both 6cm long.
Let the base of the triangle have a length of 2x.

Then the height is given by $\displaystyle x^2 + h^2 = 6^2 \Rightarrow h = \sqrt{36 - x^2}$.

You know that A = (Base)(Height)/2.

Substitute the appropriate expressions and maximise A using calculus.