Find the maximum possible area of an isosceles triangle where the two equal sides are both 6cm long.

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Originally Posted by Eric Find the maximum possible area of an isosceles triangle where the two equal sides are both 6cm long. Let the base of the triangle have a length of 2x. Then the height is given by $\displaystyle x^2 + h^2 = 6^2 \Rightarrow h = \sqrt{36 - x^2}$. You know that A = (Base)(Height)/2. Substitute the appropriate expressions and maximise A using calculus.

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