Given f(x) = 1/3 √(16-x^2), find f-1(x). Then state whether f-1(x) is a function.
Please help me solve this problem I'm desperate!!!!!!
Given f(x) = 1/3 √(16-x^2), find f-1(x). Then state whether f-1(x) is a function.
Please help me solve this problem I'm desperate!!!!!!
So, if I understand correctly. You are trying to determine whether the inverse function of f(x) is function. First, you must find the inverse function. To do this, typically one "switches" the x and y values and solves for y. So, let's do that.
flip x and y
solve for y, first multiply both side by 3
square both sides to solve to rid of the radical
now solve for y^2
take the root to isolate y
since for any x, y (your inverse function) can have 2 values the inverse is not a function