# Thread: can any one help me with thissss ?????

1. ## can any one help me with thissss ?????

find the value of "a" and "b" that makes this function continous

5b-3aX -4≤X<-2
F(X)= 4X+1 -2≤X≤2
aX˛+17b 2<X≤4

my exam is tomorrow plz wish me good luck

2. Hello,Mohamed Safy
Originally Posted by mohamedsafy
find the value of "a" and "b" that makes this function continous

5b-3aX -4≤X<-2
F(X)= 4X+1 -2≤X≤2
aX˛+17b 2<X≤4

my exam is tomorrow plz wish me good luck
for the function to b continious graph should have no breaks
so
$
5b-3a~*~-2= 4~*~-2~+~1
$

And
$
4~*~2~+~1=a~*~2^2~+~17b
$

AND ALL THE BEST for tommorow

3. ## thanks soo much

rally thank u but... i didnt get it clearly but iknow ifwe want to fnd 2nkowns "a" and "b" we have to find two equations and solve them together
what i wanted to get is how can i get these two equations ??? and everything ill be easy to me

4. ## oh

oh now i know what u wanted to say i didnt get it coz te sympols
but i still didnt get how did u find those equations

5. Originally Posted by mohamedsafy
oh now i know what u wanted to say i didnt get it coz te sympols
but i still didnt get how did u find those equations
First equation: You require the value of 5b-3aX at x = -2 to be the same as the value of 4X+1 at x = -2.

Second equation: You require the value of 4X+1 at x = 2 to be the same as the value of aX˛+17b at x = 2.

6. ## thx

thank u mr fantastic u r really fantastic