Its got me stumped...
3logx - log(x-1) + log(x+1)
hey mate,
there are three log laws that need to be employed in order to simplify your expression,
(1) nlogA = logA^n
(2) log(A) + log(B) = log(AB)
(3) log(A) - log(B) = log(A/B)
3logx - log(x-1) + log(x+1) = logx^3 - log(x-1) + log(x + 1)
= log(x^3/(x-1)) + log(x+1)
= log((x^3/(x-1))*(x+1))
or
= log(x^3(x+1)/(x-1))
Hope this helps,
Regards,
David