co ordinate geometry

**adeshSB** · November 25th 2008, 12:30 PM

can anyone help??
got this question,,
The points ABC have co ordinates (2, 1) (b,3) and (5,5) where b>3
and angle ABC=90degrees ??
I know the answer just have no idea how to work it out.

**skeeter** · November 25th 2008, 12:39 PM

(slope of AB)(slope of BC) = -1

**Plato** · November 25th 2008, 12:43 PM

In a right triangle $a^2 + b^2 = c^2$ .
So $(b-2)^2 +(3-1)^2 + (b-5)^2 + (3-5)^2 = (5-2)^2 + (5-1)^2$

**adeshSB** · November 25th 2008, 01:02 PM

does that make b= 6
cause i justtried and got some strange answer sorry i'm a bit rubbish at this

Originally Posted by Plato

In a right triangle $a^2 + b^2 = c^2$ .
So $(b-2)^2 +(3-1)^2 + (b-5)^2 + (3-5)^2 = (5-2)^2 + (5-1)^2$

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