can anyone help??

got this question,,

The points ABC have co ordinates (2, 1) (b,3) and (5,5) where b>3

and angle ABC=90degrees ??

I know the answer just have no idea how to work it out.

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- Nov 25th 2008, 12:30 PMadeshSBco ordinate geometry
can anyone help??

got this question,,

The points ABC have co ordinates (2, 1) (b,3) and (5,5) where b>3

and angle ABC=90degrees ??

I know the answer just have no idea how to work it out. - Nov 25th 2008, 12:39 PMskeeter
(slope of AB)(slope of BC) = -1

- Nov 25th 2008, 12:43 PMPlato
In a right triangle $\displaystyle a^2 + b^2 = c^2$.

So $\displaystyle (b-2)^2 +(3-1)^2 + (b-5)^2 + (3-5)^2 = (5-2)^2 + (5-1)^2$ - Nov 25th 2008, 01:02 PMadeshSB