# Thread: need some math help.

1. ## need some math help.

5. Pic 1. Find the measures of the angles of a parallelogram in which a pair of consecutive angles have measures in a ratio of 3 to 7.

m<D = ?

A. 30°
B. 54°
C. 42°
D. 26°

13. Pic 2. Use the following information to answer the question.

Given parallelogram ABCD ~ parallelogram QRST.
AB = 8, BC = 12, QR = 6, m<S = 50 degrees

A correct proportion is:

A. QT = 8/12
B. QT = 6/8
C. QT = 6/12
D. QT = 8/6

The length of line QT is:

A. 16
B. 9
C. 4
D. 8

2. ## #5

For #5, if the ratio of the consecutive angles is 3:7, make those angles 3x and 7x. If you know that the sum of the measures of the consecutive angles of a parallelogram is 180 degrees (they are supplementary), then:

3x + 7x = 180

Solve for x and substitute back into 3x or 7x depending on the diagram.

3. Originally Posted by dgenerationx2
13. Pic 2. Use the following information to answer the question.

Given parallelogram ABCD ~ parallelogram QRST.
AB = 8, BC = 12, QR = 6, m<S = 50 degrees

A correct proportion is:

A. QT = 8/12
B. QT = 6/8
C. QT = 6/12
D. QT = 8/6
I don't know what you're asking here. If you're trying to set up corresponding ratios from parallelogram ABCD to QRST, you would have $\displaystyle \frac{AB}{QR}=\frac{BC}{RS}=\frac{CD}{ST}=\frac{AD }{QT}=\frac{8}{6}$

The scale factor from ABCD to QRST is $\displaystyle \frac{8}{6}$. Is that the question you need answering? Those multiple choice answers don't make sense to me.

Originally Posted by dgenerationx2
The length of line QT is:

A. 16
B. 9
C. 4
D. 8
BC = AD and QT = RS because opposite sides of a parallelogram are of equal length.

$\displaystyle \frac{AB}{QR}=\frac{BC}{QT}$

$\displaystyle \frac{8}{6}=\frac{12}{QT}$

Solve for QT