(x-2)^2 + (y-2)^2 =2 what does the graph look like is it like a circle on the 2nd quadrant
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The graph is indeed a circle, but it is in the first quadrant. To find the radius and centre, put the equation into the form $\displaystyle (x-h)^2+(y-k)^2 = r^2$. Then (h,k) is the centre and r is the radius.
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