- Find the minimum value of the quadratic y = 2x2 - 8x + 10 by completing the square. Graph the resulting parabola.

Is this correct?

y= 2(x^2-4x)+5

y= 2(x^2-4x+4-4)+5

y= 2(x-2)^2+1

Vertex being (2,1)

If correct, how do I graph this? and which value is the minimum?