So the vertex is (2,2)
Where does the mini occur on a parabolic function?
You can graph this by plotting points with (2,2) as the vertex.
- Find the minimum value of the quadratic y = 2x2 - 8x + 10 by completing the square. Graph the resulting parabola.
Is this correct?
y= 2(x^2-4x)+5
y= 2(x^2-4x+4-4)+5
y= 2(x-2)^2+1
Vertex being (2,1)
If correct, how do I graph this? and which value is the minimum?