f(x) = 2 ( x - 4 ) ^2 how would i find the Line of symmetry if the numbers are too big to be graphed ? sorry if this sounds a bit stupid
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Let's open parentheses f(x)=2x^2-16x+32. In this equation a=2, b=-16, c=32 and it's parabola. The line symmetry is the vertical line x=-b/2a, x=16/4=4
f(x) = 2 ( x - 4 ) ^2 Let's open parentheses f(x)=2x^2-16x+32. In this equation a=2, b=-16, c=32 and it's parabola. The line symmetry is the vertical line x=-b/2a, x=16/4=4 if x = -b/2a how did you get x = 16/4 ? wouldn't it be -4/2(2) ?
If b=-16, then -b = 16, a=2, 2a=4, so -b/2a= 16/4=4
f(x) = 2 ( x - 4 ) ^2 Isn't the function in vertex form? If it is, then the axis of symm is the h value of the vertex (h,k) or in this case (4,0). line of symm x=4.
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