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Math Help - slope-intercept form

  1. #1
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    Post slope-intercept form

    my homework says: write an equation in slope-intercept form of the line satisfying the given conditions. 47. through (2,-3), parallel to 3x= 4y+5 i moved the 5 over to the other side and divided everything by 4 and i got y=3/4x - 5/4 but the real answer is y=3/4x - 9/2 what i dont get is how they got that answer... please give me the best illustration that you can. thanks!
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  2. #2
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    Quote Originally Posted by abb1327 View Post
    my homework says: write an equation in slope-intercept form of the line satisfying the given conditions. 47. through (2,-3), parallel to 3x= 4y+5 i moved the 5 over to the other side and divided everything by 4 and i got y=3/4x - 5/4 but the real answer is y=3/4x - 9/2 what i dont get is how they got that answer... please give me the best illustration that you can. thanks!

    parallel means slope is the same ( coefficient of x is the same).

    When you know that the unknown graph passes through (2,-3) you have to compose the following equation and solve it in order to find free term : -3=(3/4)*2+ a. Therefore a =-3-(3/4)*2=-18/4=-9/2. So now you know slope and free coefficient. So function is y=(3/4)*x-9/2

    have a look at the lines:
    Attached Thumbnails Attached Thumbnails slope-intercept form-untitled.jpg  
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