1. ## slope-intercept form

my homework says: write an equation in slope-intercept form of the line satisfying the given conditions. 47. through (2,-3), parallel to 3x= 4y+5 i moved the 5 over to the other side and divided everything by 4 and i got y=3/4x - 5/4 but the real answer is y=3/4x - 9/2 what i dont get is how they got that answer... please give me the best illustration that you can. thanks!

2. Originally Posted by abb1327
my homework says: write an equation in slope-intercept form of the line satisfying the given conditions. 47. through (2,-3), parallel to 3x= 4y+5 i moved the 5 over to the other side and divided everything by 4 and i got y=3/4x - 5/4 but the real answer is y=3/4x - 9/2 what i dont get is how they got that answer... please give me the best illustration that you can. thanks!

parallel means slope is the same ( coefficient of $x$ is the same).

When you know that the unknown graph passes through (2,-3) you have to compose the following equation and solve it in order to find free term : $-3=(3/4)*2+$ $a$. Therefore $a$ $=-3-(3/4)*2=-18/4=-9/2$. So now you know slope and free coefficient. So function is $y=(3/4)*x-9/2$

have a look at the lines: