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Math Help - LINEAR PROGRAMING.

  1. #1
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    Unhappy LINEAR PROGRAMING.

    A garment company makes two types of woolen sweaters and can produce a max of 700 sweaters per week. Each sweater of the first type requires 2 pounds of green wool and 4 pounds of pink wool to produce a single sweater. The second type of sweater requires 4 pounds of green wool and 3 pounds of pink wool. The profit earned the first type of sweater is $5 and on the second type $7 . The company has 50 ounds of green wool and 80 pound of pink wool.

    Write a system of inequalities to represent the number of sweaters of the first type and the number of sweaters of the second type that can be produced.


    [ i'm not sure if it's an "advanced" algebra] but i know that this isn't easy for me. PLEASE HELP ME T-T
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  2. #2
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    Quote Originally Posted by dreamgirl View Post
    A garment company makes two types of woolen sweaters and can produce a max of 700 sweaters per week. Each sweater of the first type requires 2 pounds of green wool and 4 pounds of pink wool to produce a single sweater. The second type of sweater requires 4 pounds of green wool and 3 pounds of pink wool. The profit earned the first type of sweater is $5 and on the second type $7 . The company has 50 ounds of green wool and 80 pound of pink wool.

    Write a system of inequalities to represent the number of sweaters of the first type and the number of sweaters of the second type that can be produced.


    [ i'm not sure if it's an "advanced" algebra] but i know that this isn't easy for me. PLEASE HELP ME T-T
    Hello dreamgirl,

    Let x = number of type 1
    Let y = number of type 2

    1st constraint: \boxed{x+y\leq 700}

    2nd constraint: \boxed{2x+4y\leq 50} Green wool

    3rd constraint: \boxed{4x+3y\leq 80} Pink wool

    4th constraint: \boxed{x\ge 0}

    5th constraint: \boxed{y\ge 0}

    Profit function: P(x, y)=5x+7y
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