inverse of f(x) x^3 -4

I got y=(x+4)^(1/3)

graphed it and?

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- Nov 23rd 2008, 08:30 AMrj2001inverse does not look right
inverse of f(x) x^3 -4

I got y=(x+4)^(1/3)

graphed it and? - Nov 23rd 2008, 08:35 AMRapha
- Nov 23rd 2008, 08:35 AMILoveMaths07
I think you graphed y = (x + 4^(1/3)), hence the straight line. Try again.

I hope that helps. :)

ILoveMaths07.