inverse of f(x) x^3 -4

I got y=(x+4)^(1/3)

graphed it and?

Printable View

- November 23rd 2008, 07:30 AMrj2001inverse does not look right
inverse of f(x) x^3 -4

I got y=(x+4)^(1/3)

graphed it and? - November 23rd 2008, 07:35 AMRapha
- November 23rd 2008, 07:35 AMILoveMaths07
I think you graphed y = (x + 4^(1/3)), hence the straight line. Try again.

I hope that helps. :)

ILoveMaths07.