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Math Help - pre- calc test next period need help please ...

  1. #1
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    pre- calc test next period need help please ...

    how do you write 68/4+i - 17/4-i in a+bi format?
    can anyone explain not just answer this ?
    pls
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  2. #2
    Senior Member Twig's Avatar
    Joined
    Mar 2008
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    Gothenburg
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    hi

    I assume you mean 68/4+i to mean: \frac{68}{4+i}

    We get:
    \frac{68}{4+i} - \frac{17}{4-i}
    Then you do something called multiply with the complex conjugat.
    You multiply both numerator and denominator with (focusing on the first term), you multiply with (4-i)

    So we get(still focusing on the first term):
    \frac{68(4-i)}{(4+i)(4-i)}
    Simplify this... \frac{68(4-i)}{17}

    You do the same thing on the second term, and add them togheter.

    Hope this helped you out
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  3. #3
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    yeah thanks
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