how do you write 68/4+i - 17/4-i in a+bi format?
can anyone explain not just answer this ?
pls
I assume you mean 68/4+i to mean: $\displaystyle \frac{68}{4+i}$
We get:
$\displaystyle \frac{68}{4+i} - \frac{17}{4-i}$
Then you do something called multiply with the complex conjugat.
You multiply both numerator and denominator with (focusing on the first term), you multiply with $\displaystyle (4-i)$
So we get(still focusing on the first term):
$\displaystyle \frac{68(4-i)}{(4+i)(4-i)} $
Simplify this... $\displaystyle \frac{68(4-i)}{17} $
You do the same thing on the second term, and add them togheter.
Hope this helped you out