(Crying)how do you write 68/4+i - 17/4-i in a+bi format?

can anyone explain not just answer this ?

pls :)

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- Nov 21st 2008, 05:50 AMIronscorppre- calc test next period need help please ...
*(Crying)how do you write 68/4+i - 17/4-i in a+bi format?*

can anyone explain not just answer this ?

pls :) - Nov 21st 2008, 09:54 AMTwighi
I assume you mean 68/4+i to mean:

We get:

Then you do something called multiply with the complex conjugat.

You multiply both numerator and denominator with (focusing on the first term), you multiply with

So we get(still focusing on the first term):

Simplify this...

You do the same thing on the second term, and add them togheter.

Hope this helped you out - Nov 25th 2008, 05:28 AMIronscorp
yeah thanks :)