The weight of an object varies inversely with square of distance from earth's center (3960 miles). A man weighs 250 lbs on the surface of the earth. How much would he weigh in an airplane flying at 30,000 ft?
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Let W denote the weight of the man. Then from the relationship given in the problem with d denoting the distance from the core of earth gives : $\displaystyle W \alpha \frac{1}{d^2} \Rightarrow 250 \cdot \frac{1}{\frac{3965.68}{3960}^2}=249.28 $
Originally Posted by Pur Let W denote the weight of the man. Then from the relationship given in the problem with d denoting the distance from the core of earth gives : $\displaystyle W \alpha \frac{1}{d^2} \Rightarrow 250 \cdot \frac{1}{\frac{3965.68}{3960}^2}=249.28 $ What a nice job!
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