e^(x) + e^(-x) = 5...solve for x.
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Multiply your equation by $\displaystyle e^x,$ and then put $\displaystyle z=e^x,$ you're gonna have to deal with a quadratic equation.
Originally Posted by Krizalid Multiply your equation by $\displaystyle e^x,$ and then put $\displaystyle z=e^x,$ you're gonna have to deal with a quadratic equation. Can you be more specific?
Originally Posted by magentarita Can you be more specific? No. I want you to try to do what I said.
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