A quadratic equation x^2 + bx + c = 0 has complex roots 3+6i and 3-6i. Find the values of b and c.

Thank you for any help!

2. Originally Posted by live_laugh_luv27
A quadratic equation x^2 + bx + c = 0 has complex roots 3+6i and 3-6i. Find the values of b and c.

Thank you for any help!
hint: the coefficients of the x-squared term in the quadratic is 1, thus the quadratic is given by $(x - r_1)(x - r_2)$, where $r_1$ and $r_2$ are the two roots of the equation

3. Originally Posted by Jhevon
hint: the coefficients of the x-squared term in the quadratic is 1, thus the quadratic is given by $(x - r_1)(x - r_2)$, where $r_1$ and $r_2$ are the two roots of the equation

So, would you do (1-(3+6i )) and (1-(3-6i))??

4. Originally Posted by live_laugh_luv27
So, would you do (1-(3+6i )) and (1-(3-6i))??
i have no idea how you got that

to follow up on what i said, start with $(x - 3 - 6i)(x - 3 + 6i)$

now multiply out and you can find b and c

5. Originally Posted by Jhevon
i have no idea how you got that

to follow up on what i said, start with $(x - 3 - 6i)(x - 3 + 6i)$

now multiply out and you can find b and c

Thank you so much for your help!!

6. Originally Posted by live_laugh_luv27
Thank you so much for your help!!
you're welcome

7. Originally Posted by Jhevon
you're welcome

b = -9, c=45

8. Originally Posted by live_laugh_luv27
b = -9, c=45
b is incorrect

9. -6 !!!!!!!!!!!

10. Originally Posted by live_laugh_luv27
-6 !!!!!!!!!!!
um, yes...!!!!!!!!!!!!

11. Originally Posted by Jhevon
um, yes...!!!!!!!!!!!!