A quadratic equation x^2 + bx + c = 0 has complex roots 3+6i and 3-6i. Find the values of b and c. Thank you for any help!
Follow Math Help Forum on Facebook and Google+
Originally Posted by live_laugh_luv27 A quadratic equation x^2 + bx + c = 0 has complex roots 3+6i and 3-6i. Find the values of b and c. Thank you for any help! hint: the coefficients of the x-squared term in the quadratic is 1, thus the quadratic is given by , where and are the two roots of the equation
Originally Posted by Jhevon hint: the coefficients of the x-squared term in the quadratic is 1, thus the quadratic is given by , where and are the two roots of the equation So, would you do (1-(3+6i )) and (1-(3-6i))??
Originally Posted by live_laugh_luv27 So, would you do (1-(3+6i )) and (1-(3-6i))?? i have no idea how you got that to follow up on what i said, start with now multiply out and you can find b and c
Originally Posted by Jhevon i have no idea how you got that to follow up on what i said, start with now multiply out and you can find b and c Thank you so much for your help!!
Originally Posted by live_laugh_luv27 Thank you so much for your help!! you're welcome state your answer when done
Originally Posted by Jhevon you're welcome state your answer when done b = -9, c=45
Originally Posted by live_laugh_luv27 b = -9, c=45 b is incorrect
-6 !!!!!!!!!!!
Originally Posted by live_laugh_luv27 -6 !!!!!!!!!!! um, yes...!!!!!!!!!!!!
Originally Posted by Jhevon um, yes...!!!!!!!!!!!! thanks again for your help I appreciate it
View Tag Cloud