Vanessa throws a tennis ball in the air.
The function h(t) = –16t^2 + 45t + 7 represents the distance, in feet, that the ball is from the ground at any
time t. At what time, to the nearest tenth of a second, is the ball at its maximum height?
Vanessa throws a tennis ball in the air.
The function h(t) = –16t^2 + 45t + 7 represents the distance, in feet, that the ball is from the ground at any
time t. At what time, to the nearest tenth of a second, is the ball at its maximum height?
Hello, magentarita!
The graph is a down-opening parabola. .Its maximum is at its vertex.Vanessa throws a tennis ball in the air.
The function $\displaystyle h(t) \:=\:–16 t^2+ 45t+ 7$ represents the distance, in feet,
that the ball is from the ground at any time $\displaystyle t$.
At what time, to the nearest tenth of a second, is the ball at its maximum height?
The vertex is: .$\displaystyle t \:=\:\frac{\text{-}b}{2a} \:=\:\frac{\text{-}45}{2(\text{-}16)} \:=\:\frac{45}{32}\:=\:1.40625$
The ball is at maximum height in about 1.4 seconds.