Vanessa throws a tennis ball in the air.

The function h(t) = –16t^2 + 45t+ 7 represents the distance, in feet, that the ball is from the ground at any

timet. At what time, to thenearest tenth of a second,is the ball at its maximum height?

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- Nov 17th 2008, 10:23 PMmagentaritaBall At Max HeightVanessa throws a tennis ball in the air.

The function h(*t*) = –16*t^*2 + 45*t*+ 7 represents the distance, in feet, that the ball is from the ground at any

time*t*. At what time, to the*nearest tenth of a second,*is the ball at its maximum height?

- Nov 18th 2008, 11:24 AMSoroban
Hello, magentarita!

Quote:

Vanessa throws a tennis ball in the air.

The function $\displaystyle h(t) \:=\:–16 t^2+ 45t+ 7$ represents the distance, in feet,

that the ball is from the ground at any time $\displaystyle t$.

At what time, to the nearest tenth of a second, is the ball at its maximum height?

The vertex is: .$\displaystyle t \:=\:\frac{\text{-}b}{2a} \:=\:\frac{\text{-}45}{2(\text{-}16)} \:=\:\frac{45}{32}\:=\:1.40625$

The ball is at maximum height in about 1.4 seconds.

- Nov 18th 2008, 09:35 PMmagentaritagreat work...........