determine the equation of the tangent line to the curve
f(x)=4x^3(x-2)^4(6x-5)^5 at point (1,4)
can u just help to get F'(x) then i know how to plug 1 in f'(X).
please help and show solution
use the product rule (with the chain rule where necessary) and note that:
if $\displaystyle f, g, \text{ and } h$ are functions of $\displaystyle x$, then
$\displaystyle \frac d{dx} [fgh] = f'gh + fg'h + fgh'$
here you can let $\displaystyle f = 4x^3$, $\displaystyle g = (x - 2)^4$, and $\displaystyle h = (6x - 5)^5$
and note that you need the chain rule to find $\displaystyle g'$ and $\displaystyle h'$