determine the equation of the tangent line to the curve f(x)=4x^3(x-2)^4(6x-5)^5 at point (1,4) can u just help to get F'(x) then i know how to plug 1 in f'(X). please help and show solution
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Originally Posted by Max10 determine the equation of the tangent line to the curve f(x)=4x^3(x-2)^4(6x-5)^5 at point (1,4) can u just help to get F'(x) then i know how to plug 1 in f'(X). please help and show solution use the product rule (with the chain rule where necessary) and note that: if are functions of , then here you can let , , and and note that you need the chain rule to find and
so is it f'(x) 12x^2 g'(x)=4(x-2)^3(x) h'(x)=5(6x-5)^4(6)
Originally Posted by Max10 so is it f'(x) 12x^2 g'(x)=4(x-2)^3(x) h'(x)=5(6x-5)^4(6) your g'(x) is wrong
Originally Posted by Jhevon your g'(x) is wrong how come (x-2)^4 g'(x) 4(x-2)^3(x) please help
Originally Posted by Max10 how come (x-2)^4 g'(x) 4(x-2)^3(x) please help the derivative of x - 2 is not x...
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