The expression log10^(x + 2) - log10^(x) is equivalent to:
(a) -2
(b) 2
(c) 100
(d) 1/100
I don't just want the answer. I want to know how to find it.
Thanks
The only way any of those can be correct is if "log" is common logarithm or log base 10. In that case, the problem is $\displaystyle log_{10} 10^{x+2}- log_{10}10^x$. Now what is $\displaystyle log_{10} 10^a$ for any real number a?