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Math Help - Logs

  1. #1
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    Logs

    The expression log10^(x + 2) - log10^(x) is equivalent to:

    (a) -2

    (b) 2

    (c) 100

    (d) 1/100

    I don't just want the answer. I want to know how to find it.

    Thanks
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  2. #2
    MHF Contributor

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    Quote Originally Posted by magentarita View Post
    The expression log10^(x + 2) - log10^(x) is equivalent to:

    (a) -2

    (b) 2

    (c) 100

    (d) 1/100

    I don't just want the answer. I want to know how to find it.

    Thanks
    The only way any of those can be correct is if "log" is common logarithm or log base 10. In that case, the problem is log_{10} 10^{x+2}- log_{10}10^x. Now what is log_{10} 10^a for any real number a?
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