# Math Help - Logs

1. ## Logs

The expression log10^(x + 2) - log10^(x) is equivalent to:

(a) -2

(b) 2

(c) 100

(d) 1/100

I don't just want the answer. I want to know how to find it.

Thanks

2. Originally Posted by magentarita
The expression log10^(x + 2) - log10^(x) is equivalent to:

(a) -2

(b) 2

(c) 100

(d) 1/100

I don't just want the answer. I want to know how to find it.

Thanks
The only way any of those can be correct is if "log" is common logarithm or log base 10. In that case, the problem is $log_{10} 10^{x+2}- log_{10}10^x$. Now what is $log_{10} 10^a$ for any real number a?