f(x)=2x squared-2x+2;domain=(-4,-2,0,4)

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- Jul 17th 2005, 06:37 PMAshiebug3find the range of the function
f(x)=2x squared-2x+2;domain=(-4,-2,0,4)

- Jul 17th 2005, 11:19 PMrgep
First let's clarify the terminology. If f is a function from set X to set Y then X is the

*domain*and Y is the*codomain*. The set f(X) = {f(x) : x in X} of values actually taken by X is the*image*. Unfortunately the terminology is not completely fixed and the codomain is also called the target or range and the image is also called the range by some authors. In your case you want the image. The domain is the four-element set {-4,-2,0,4}, the codomain is the real numbers. The range is the set of actual values taken, namely {f(-4), f(-2), f(0), f(4)}. You need to compute these and then write the set of those values. (Notice that if a value is taken more than once it only appears once in the set) - Jul 19th 2005, 08:11 PMAshiebug3Find the range of the function
I still do not understand what i am to do with this problem. Can someone show me how to do it?

f(x)=2x squared-2x+2

domain= (-4,-2,0,4)