The hyperbolic cosine function, designated by cosh x is defined as cosh x = (1/2) (e^x + e^(-x)). Show that f(x) = cosh x is an even number.
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An even funtion satisfies $\displaystyle f(x)=f(-x).$ In the same fashion of your other problem (odd hyperbolic sin function), do it.
Originally Posted by magentarita The hyperbolic cosine function, designated by cosh x is defined as cosh x = (1/2) (e^x + e^(-x)). Show that f(x) = cosh x is an even number. That is NOT what the questions asks because it makes no sense. cosh x is an even FUNCTION not an even number.
Originally Posted by Krizalid An even funtion satisfies $\displaystyle f(x)=f(-x).$ In the same fashion of your other problem (odd hyperbolic sin function), do it. Are you saying to replace x with -x in the given function and simplify?
Originally Posted by HallsofIvy That is NOT what the questions asks because it makes no sense. cosh x is an even FUNCTION not an even number. What is the correct method for solving this question?
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