find the radius and center of
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Originally Posted by ea12345 find the radius and center of The general equation of a circle of radius r and centre at (h, k) is $\displaystyle (x - h)^2 + (y - k)^2 = r^2$.
actual equation is
Originally Posted by ea12345 actual equation is Complete the square: $\displaystyle (x + 4)^2 - 16 + 8 + y^2 = 0 \Rightarrow (x + 4)^2 + y^2 = 8$. Now read again my first post.
x2 + y2 + 8x + 8 = 0 x2 + 8x + (4)2 + (y – 0)2 = -8 + x2 (x + 4)2 + (y – 0)2 = 8 (x – (-4) )2 +(y – 0)2 =( ) (x –(-x) )2 + (y – 0) = (2 ) SO, centre is (-4 , 0) and radius is 2 its true or not ?
Originally Posted by ea12345 x2 + y2 + 8x + 8 = 0 x2 + 8x + (4)2 + (y – 0)2 = -8 + x2 (x + 4)2 + (y – 0)2 = 8 (x – (-4) )2 +(y – 0)2 =( ) (x –(-x) )2 + (y – 0) = (2 ) SO, centre is (-4 , 0) and radius is 2 its true or not ? The radius is not 2.
then
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