$\displaystyle Log base 2 (x-6)=3$ Any help will be appreciated. Thnks in advance
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in general $\displaystyle \log _a b = c \Leftrightarrow a^c = b $ in this case $\displaystyle \log _2 \left( {x - 6} \right) = 3 \Leftrightarrow 2^3 = x - 6 $
Thanks man
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