Substitute and solve simultaneously for c and k. eg. for the first question you have

and

Results 1 to 10 of 10

- November 3rd 2008, 03:58 PM #1

- Joined
- Oct 2008
- Posts
- 35

- November 3rd 2008, 04:03 PM #2

- Joined
- Dec 2007
- From
- Melbourne
- Posts
- 428

- November 3rd 2008, 04:05 PM #3

- Joined
- Oct 2008
- Posts
- 35

- November 3rd 2008, 04:05 PM #4

- Joined
- Oct 2005
- From
- Earth
- Posts
- 1,599
- Thanks
- 1

- November 3rd 2008, 05:05 PM #5

- Joined
- Oct 2008
- Posts
- 35

- November 3rd 2008, 05:12 PM #6

- Joined
- Oct 2005
- From
- Earth
- Posts
- 1,599
- Thanks
- 1

Ok you need to think about your function, F(t), and what every letter represents. I solved for c and k. They are both constants defined by the two points in part (a). For part (b) they will change. e is a constant number 2.71... which is Euler's constant. If you are unfamiliar with this, you should look it up. Now you wrote in the title of this thread, F(x), not F(t). Think about this. If F is a function dependent on x, why are there no x's in the equation? If x isn't the variable, what is? t is. Or you need to change it to F(x)=ce^{kx}. Either way, but you need to be consistent.

So, you have c and k (constants) and e (always a constant), so this problem is completed.

- November 3rd 2008, 05:22 PM #7

- Joined
- Oct 2008
- Posts
- 35

- November 3rd 2008, 05:26 PM #8

- Joined
- Oct 2005
- From
- Earth
- Posts
- 1,599
- Thanks
- 1

- November 3rd 2008, 05:27 PM #9

- Joined
- Oct 2008
- Posts
- 35

- November 3rd 2008, 05:32 PM #10

- Joined
- Oct 2005
- From
- Earth
- Posts
- 1,599
- Thanks
- 1

Click on a term to search for related topics.