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Math Help - Wire of Length x

  1. #1
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    Wire of Length x

    A wire of length x is bent into the shape of a square.

    (a) Express the perimeter of the square as a function of x.

    (b) Express the area of the square as a function of x.
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  2. #2
    Senior Member Peritus's Avatar
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    1. P = x
    2. S = (x/4)^2
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  3. #3
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    ok but...

    Quote Originally Posted by Peritus View Post
    1. P = x
    2. S = (x/4)^2
    I understand your reply but how did you come up with the answers?
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  4. #4
    A riddle wrapped in an enigma
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    Quote Originally Posted by magentarita View Post
    I understand your reply but how did you come up with the answers?
    A wire of length x bent into a square would make each side \frac{1}{4}x

    Perimeter of the square P(x)=\frac{1}{4}x+\frac{1}{4}x+\frac{1}{4}x+\frac{  1}{4}x=\frac{4}{4}x=x

    Area of the square would be A(x)=\left(\frac{1}{4}x\right)^2=\frac{1}{16}x^2
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  5. #5
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    wonderful...........

    Quote Originally Posted by masters View Post
    A wire of length x bent into a square would make each side \frac{1}{4}x

    Perimeter of the square P(x)=\frac{1}{4}x+\frac{1}{4}x+\frac{1}{4}x+\frac{  1}{4}x=\frac{4}{4}x=x

    Area of the square would be A(x)=\left(\frac{1}{4}x\right)^2=\frac{1}{16}x^2
    Wonderful. Your replies are so helpful.
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