# Thread: Wire of Length x

1. ## Wire of Length x

A wire of length x is bent into the shape of a square.

(a) Express the perimeter of the square as a function of x.

(b) Express the area of the square as a function of x.

2. 1. P = x
2. S = (x/4)^2

3. ## ok but...

Originally Posted by Peritus
1. P = x
2. S = (x/4)^2

4. Originally Posted by magentarita
A wire of length x bent into a square would make each side $\frac{1}{4}x$

Perimeter of the square $P(x)=\frac{1}{4}x+\frac{1}{4}x+\frac{1}{4}x+\frac{ 1}{4}x=\frac{4}{4}x=x$

Area of the square would be $A(x)=\left(\frac{1}{4}x\right)^2=\frac{1}{16}x^2$

5. ## wonderful...........

Originally Posted by masters
A wire of length x bent into a square would make each side $\frac{1}{4}x$

Perimeter of the square $P(x)=\frac{1}{4}x+\frac{1}{4}x+\frac{1}{4}x+\frac{ 1}{4}x=\frac{4}{4}x=x$

Area of the square would be $A(x)=\left(\frac{1}{4}x\right)^2=\frac{1}{16}x^2$

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# A wire of length x is bent into the shape of a square. Express the area of the square as a function of x

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