A wire of length x is bent into the shape of a square.

(a) Express the perimeter of the square as a function of x.

(b) Express the area of the square as a function of x.

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- Nov 3rd 2008, 06:08 AMmagentaritaWire of Length x
A wire of length x is bent into the shape of a square.

(a) Express the perimeter of the square as a function of x.

(b) Express the area of the square as a function of x.

- Nov 3rd 2008, 06:24 AMPeritus
1. P = x

2. S = (x/4)^2 - Nov 4th 2008, 05:45 AMmagentaritaok but...
- Nov 4th 2008, 07:12 AMmasters
A wire of length

**x**bent into a square would make each side $\displaystyle \frac{1}{4}x$

Perimeter of the square $\displaystyle P(x)=\frac{1}{4}x+\frac{1}{4}x+\frac{1}{4}x+\frac{ 1}{4}x=\frac{4}{4}x=x$

Area of the square would be $\displaystyle A(x)=\left(\frac{1}{4}x\right)^2=\frac{1}{16}x^2$ - Nov 4th 2008, 08:50 PMmagentaritawonderful...........