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Hello, im doing this math homework in quadratics and i cant figure out this one
Determine the equation (in standard form) of the parabola that has a y-intercept of 3, and that passes through the points (1,9) and (-2,15)
this is supposed to be an inquiry question, i guess its relatevely easy but i dont know which one is the vertex and how do i use the y-intercept to help me solve it?
you have three points ... (0,3) , (1,9) , and (-2,15)Quote:
Determine the equation (in standard form) of the parabola that has a y-intercept of 3, and that passes through the points (1,9) and (-2,15)
using the form $\displaystyle y = ax^2 + bx + c$ , you can set up three equations ...
$\displaystyle a(0)^2 + b(0) + c = 3$
$\displaystyle a(1)^2 + b(1) + c = 9$
$\displaystyle a(-2)^2 + b(-2) + c = 15$
solve the system for the coefficients of the terms in the quadratic, a, b, and c.
