Please help me change this standard form of a parabola to vertex form. y = 0.2955x^2 + 0.1811x + 22.382 If possible, please use the -b/2a version instead of completing the square, because that is what I was taught. Thank you for any help!
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Originally Posted by live_laugh_luv27 Please help me change this standard form of a parabola to vertex form. y = 0.2955x^2 + 0.1811x + 22.382 If possible, please use the -b/2a version instead of completing the square, because that is what I was taught. Thank you for any help! completing the square for
Last edited by Jhevon; Nov 1st 2008 at 01:19 PM. Reason: forgot to square the 2, thanks Shyam
Originally Posted by live_laugh_luv27 Please help me change this standard form of a parabola to vertex form. y = 0.2955x^2 + 0.1811x + 22.382 If possible, please use the -b/2a version instead of completing the square, because that is what I was taught. Thank you for any help! The vertex is here, a = 0.2955, b = 0.1811, c = 22.382
Originally Posted by Shyam The vertex is here, a = 0.2955, b = 0.1811, c = 22.382 Thank you so much!!
One question -- One post has k= 2ac – b2/2a, the other has k= 4ac – b2/2a. Who is correct? Thanks!
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