1. ## Test coming up, Review study ?'s Vertex,quadratics etc

Have a test coming up so I want to make sure my review is right. Got a little help in the precalc room but the test is on wed so if anyone can look through problems 3 thru 7 even if its just one id be greatful. Thanks in advance

2. recheck your solutions to #5 and #7.

3. hey thanks ill do that, The other questions are right I take it? Man your very helpful

4. for number 5, try squaring both sides
and then expanding right side the question out
then combine all like terms on one side of the equals sign
and solve for the 2 values of x

*hint: the answer is one of the choices

5. Ok I think I fixed 5 and am sorta sure that I did 7 right. Thanks to all for checking!

6. #5 ...

$\displaystyle \sqrt{x+5} = x+3$

$\displaystyle x+5 = x^2 + 6x + 9$

$\displaystyle 0 = x^2 + 5x + 4$

$\displaystyle 0 = (x+1)(x+4)$

$\displaystyle x = -1$ or $\displaystyle x = -4$

one of these solutions is extraneous ... you check it.

#7 ...

$\displaystyle |5-x| < 4$

$\displaystyle |x-5| < 4$

$\displaystyle -4 < x-5 < 4$

$\displaystyle 1 < x < 9$