Have a test coming up so I want to make sure my review is right. Got a little help in the precalc room but the test is on wed so if anyone can look through problems 3 thru 7 even if its just one id be greatful. Thanks in advance
Have a test coming up so I want to make sure my review is right. Got a little help in the precalc room but the test is on wed so if anyone can look through problems 3 thru 7 even if its just one id be greatful. Thanks in advance
#5 ...
$\displaystyle \sqrt{x+5} = x+3$
$\displaystyle x+5 = x^2 + 6x + 9$
$\displaystyle 0 = x^2 + 5x + 4$
$\displaystyle 0 = (x+1)(x+4)$
$\displaystyle x = -1$ or $\displaystyle x = -4$
one of these solutions is extraneous ... you check it.
#7 ...
$\displaystyle |5-x| < 4$
$\displaystyle |x-5| < 4$
$\displaystyle -4 < x-5 < 4$
$\displaystyle 1 < x < 9$