hi, dont think that make any sense something is not right.whats the original question.
Hello all,
I was hoping for some help on turning complex number to polar form. I'm working on a nonhomogenous difference equation, and while solving I got the roots .
Ok, so far so good. The modulus, , which gives me . Then the argument, . This gives me . Is this correct?
The root I got, , when I want to find , what value of b do I use (because of the )? The negative or positive value of ?
Is there any way to make the argument a "pretty" -fraction (if it exists)?
Thank you for any help!
actually it does make sense sorry i was only glancing afeter i start thinking about it.anyways.let z=3/4 ± i√7/8 (rember that i=√-1 and the √-7/8 is the same as √-1 times √7 ok) polar form =r[cos(θ)+isin(θ)]
[z]=r=√(a^2+b^2)=85/64 (note that r is indeed the modulus of z)
arg(z)=tan(θ)=6/7
θ=tan^-1(6/7)
θ=40.60
therefore
arg(z)=40.60 (you can convert to pi radians if you want ok)
now we have everything to represent in polar form so now substitute.
polar form of Z=85/64[cos(40.60) + isin(40.60)]. (the squared root of any -number does not exist thats its imaginary thats why i is used to replace √-n=i ok.) good luck hope this helps and talk to me if you need anything else god be with you.