Hey guys first post so be gentle
Came across this question here and really have no idea can someone help me out? Also am not sure how advanced it has to be to be in this section so I apologize if that's wrong. I just saw university level and since I'm at uni doing this I guessed would be a good place to put it.
Here's the question.
Thanks in advance.
hey john. actually that question is not that difficult. here goes. given that z=sqrt3-i. polar form is r[cos(theta)+isin(theta)] where r is the modulus of z. modulus of [z]=r=sqrta^6+b^2=2.(a=sqrt3 and b=-1) and the argument is arg(z)=-sqrt3/1=-60 so the polar form is after substituting what the unknows are and fix nicely; 2[cos(-60)+isin(-60)] NOTE that r is also the modulus or the distance. let me know wha you think
b).promise i'll get you b shortly
i think this would be the answer for part b'. first work z^7 and that is equal; z^7=re^i(theta)=7[cos(theta)+isin(theta)]. but it is divided by 8 and the question wants the imaginary and the the real seperate. so
we 7[cos(theta)+isin(theta)]/8. now the real=7[cos(theta)/8 and Im=isin(theta)]/8 and solve your answer.looking forward to hear from you or anyone.