The equation is y=3/5 x -5 a. what is the slope of a line parallel to it? b. what is the line perpendicular to it? Find the indicated value f(x)=3-5x
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Originally Posted by Miserable The equation is y=3/5 x -5 a. what is the slope of a line parallel to it? b. what is the line perpendicular to it? Find the indicated value f(x)=3-5x The slope is m=3/5 A perpendicular line must have a negative reciprocal, that is, -5/3
Thanks for the first help. Can you help with the next problem? f(x)=3-5x
Originally Posted by Miserable Thanks for the first help. Can you help with the next problem? f(x)=3-5x For the price of thy soul, of course. The slope is in front of the 'x' which is, m=-5 The negative reciprocal is, m=1/5
Thank you
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