Thread: Algebra

The equation is y=3/5 x -5
a. what is the slope of a line parallel to it?
b. what is the line perpendicular to it?

Find the indicated value

f(x)=3-5x

Originally Posted by Miserable

The equation is y=3/5 x -5
a. what is the slope of a line parallel to it?
b. what is the line perpendicular to it?

Find the indicated value

f(x)=3-5x

The slope is m=3/5

A perpendicular line must have a negative reciprocal, that is,
-5/3

Thanks for the first help. Can you help with the next problem?
f(x)=3-5x

Originally Posted by Miserable

Thanks for the first help. Can you help with the next problem?
f(x)=3-5x

For the price of thy soul, of course.

The slope is in front of the 'x' which is,
m=-5
The negative reciprocal is,
m=1/5

Thank you