# Algebra

• Sep 20th 2006, 07:35 AM
Miserable
Algebra
The equation is y=3/5 x -5
a. what is the slope of a line parallel to it?:confused:
b. what is the line perpendicular to it?:confused:

Find the indicated value

f(x)=3-5x:confused:
• Sep 20th 2006, 07:37 AM
ThePerfectHacker
Quote:

Originally Posted by Miserable
The equation is y=3/5 x -5
a. what is the slope of a line parallel to it?:confused:
b. what is the line perpendicular to it?:confused:

Find the indicated value

f(x)=3-5x:confused:

The slope is m=3/5

A perpendicular line must have a negative reciprocal, that is,
-5/3
• Sep 20th 2006, 07:58 AM
Miserable
Thanks for the first help. Can you help with the next problem?
f(x)=3-5x
:confused:
• Sep 20th 2006, 08:00 AM
ThePerfectHacker
Quote:

Originally Posted by Miserable
Thanks for the first help. Can you help with the next problem?
f(x)=3-5x
:confused:

For the price of thy soul, of course.

The slope is in front of the 'x' which is,
m=-5
The negative reciprocal is,
m=1/5
• Sep 20th 2006, 08:03 AM
Miserable
Thank you

:)