In the xy-plane, what is the area of a triangle whose vertices are , , and ? (A) 3.59 (B) 5.67 (C) 7.91 (D) 11.18 (E) 11.34
Follow Math Help Forum on Facebook and Google+
$\displaystyle A = \frac{1}{2}bh = \frac{1}{2}(5 - \sqrt{2})(\sqrt{10})$
Originally Posted by skeeter $\displaystyle A = \frac{1}{2}bh = \frac{1}{2}(5 - \sqrt{2})(\sqrt{10})$ how did you get b as 5-sqrt2? Thanks again!!
the points on the x-axis are $\displaystyle (5,0)$ and $\displaystyle (\sqrt{2},0)$ the distance between those two values is $\displaystyle 5 - \sqrt{2}$
View Tag Cloud