A right triangle has one vertex on the graph of
y = 9 - x^2, x > 0, at (x, y), another at the origin, and the thiurd on the positive x-axis at (x, 0). Express the area A of the triangle as a function of x.
Hello, magentarita!
Henderson is absolutely correct!
Did you make a sketch? . . . It's very simple.
A right triangle has one vertex on the graph of
another at the origin, and the third on the positive x-axis at (x, 0).
Express the area of the triangle as a function ofCode:| 9 ** | * P | *(x,y) | *:| * | *:::| * | *:::::| - + - - - + - * - - O Q 3
The area of a triangle is: .
The base is
The height is , where
Therefore: .