A right triangle has one vertex on the graph of

y = 9 - x^2, x > 0, at (x, y), another at the origin, and the thiurd on the positive x-axis at (x, 0). Express the area A of the triangle as a function of x.

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- Oct 29th 2008, 08:00 AMmagentaritaRight Triangle
A right triangle has one vertex on the graph of

y = 9 - x^2, x > 0, at (x, y), another at the origin, and the thiurd on the positive x-axis at (x, 0). Express the area A of the triangle as a function of x.

- Oct 29th 2008, 08:17 AMHenderson
The base of your triangle is your x-coordinate, and the height of the triangle is your y-coordinate. For a triangle, the area is given by

, so

- Oct 29th 2008, 08:54 AMSoroban
Hello, magentarita!

Henderson is absolutely correct!

Did you make a sketch? . . . It's very simple.

Quote:

A right triangle has one vertex on the graph of

another at the origin, and the third on the positive x-axis at (x, 0).

Express the area of the triangle as a function of

Code:`|`

9 **

| * P

| *(x,y)

| *:| *

| *:::| *

| *:::::|

- + - - - + - * - -

O Q 3

The area of a triangle is: .

The base is

The height is , where

Therefore: .

- Oct 29th 2008, 06:13 PMmagentaritagreat work....
- Oct 29th 2008, 06:14 PMmagentaritaSoroban....