For the piecewise-defined below, find:
f(-2), f(0) and f(2)
.........{x^2..........if x < 0
f(x) = {2..............if x = 0
.........{2x + 1.......if x > 0
Which of these piecewise functions is defined for negative values of x (i.e. x<0)? Substitute -2 into that function to get the value of f(-2).
There is only one function that is defined at x=0. So what do you think f(0) would be?
Which of these piecewise functions is defined for positive values of x (i.e. x>0)? Substitute 2 into that function to get the value of f(2).
Does this make sense?
--Chris
Sure.
I'll evaluate
Since , you want to focus on the function that is defined for . Looking at the piecewise function, we see something:
We see that the function defined for is . So we can now say that
Does this clarify things? Can you try the others on your own?
--Chris