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Math Help - another vertex question..

  1. #1
    Junior Member
    Joined
    Sep 2008
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    another vertex question..

    I need to find the vertex of the parabola y=6x^2-5x+28
    I found found x, which is 5/12 but I can't seem to find the y...
    I used the formula
    (-b/2a, c-b^2/4a) I'm not sure why I can get the first part but not the second part.
    Any help would be greatly appreciated!
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  2. #2
    Super Member 11rdc11's Avatar
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    Quote Originally Posted by epetrik View Post
    I need to find the vertex of the parabola y=6x^2-5x+28
    I found found x, which is 5/12 but I can't seem to find the y...
    I used the formula
    (-b/2a, c-b^2/4a) I'm not sure why I can get the first part but not the second part.
    Any help would be greatly appreciated!
    just plug in the x you found back into your original equation

    y=6\bigg(\frac{5}{12}\bigg)^2 -5\bigg(\frac{5}{12}\bigg) +28
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