# another vertex question..

• Oct 28th 2008, 02:11 PM
epetrik
another vertex question..
I need to find the vertex of the parabola y=6x^2-5x+28
I found found x, which is 5/12 but I can't seem to find the y...
I used the formula
(-b/2a, c-b^2/4a) I'm not sure why I can get the first part but not the second part.
Any help would be greatly appreciated!
:)
• Oct 28th 2008, 02:16 PM
11rdc11
Quote:

Originally Posted by epetrik
I need to find the vertex of the parabola y=6x^2-5x+28
I found found x, which is 5/12 but I can't seem to find the y...
I used the formula
(-b/2a, c-b^2/4a) I'm not sure why I can get the first part but not the second part.
Any help would be greatly appreciated!
:)

just plug in the x you found back into your original equation

$y=6\bigg(\frac{5}{12}\bigg)^2 -5\bigg(\frac{5}{12}\bigg) +28$