Find radius and center of the equations

Thanks

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- Oct 28th 2008, 09:38 AMea12345Radius and Center
Find radius and center of the equations

Thanks - Oct 28th 2008, 10:12 AMThePerfectHacker
1)Add 16 to both sides $\displaystyle x^2+8x+16 + 8 + y^2= 16 \implies (x +4)^2 + y^2 = (\sqrt{8})^2$

What is the radius and center?

2)Multiply by 4 to get $\displaystyle x^2+y^2 = 2^2$.

What is the radius and center? - Oct 30th 2008, 06:06 AMea12345"y2" not in my question
dear "y2" not in my question..........

- Oct 30th 2008, 01:09 PMHallsofIvy
I have no idea what that means!

- Oct 31st 2008, 12:00 AMea12345help
I mean y square is not in the equation