• Oct 28th 2008, 09:38 AM
ea12345
Find radius and center of the equations

Thanks
• Oct 28th 2008, 10:12 AM
ThePerfectHacker
1)Add 16 to both sides $x^2+8x+16 + 8 + y^2= 16 \implies (x +4)^2 + y^2 = (\sqrt{8})^2$
What is the radius and center?

2)Multiply by 4 to get $x^2+y^2 = 2^2$.
What is the radius and center?
• Oct 30th 2008, 06:06 AM
ea12345
"y2" not in my question
dear "y2" not in my question..........
• Oct 30th 2008, 01:09 PM
HallsofIvy
I have no idea what that means!
• Oct 31st 2008, 12:00 AM
ea12345
help
I mean y square is not in the equation